x^2+0.32x-0.0255=0

Solution for x^2+0.32x-0.0255=0 equation:

x^2+0.32x-0.0255=0

a = 1; b = 0.32; c = -0.0255;
Δ = b2-4ac
Δ = 0.322-4·1·(-0.0255)
Δ = 0.2044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.32)-\sqrt{0.2044}}{2*1}=\frac{-0.32-\sqrt{0.2044}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.32)+\sqrt{0.2044}}{2*1}=\frac{-0.32+\sqrt{0.2044}}{2}
$